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ExamBoxer ASVAB

  • Armed Services Vocational Aptitude Battery

ASVAB

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A
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Answer: A

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Anonymous (dca0)
A
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A
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Answer: C

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Anonymous (b8a8)
A
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Answer: C

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Anonymous (fc71)
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Answer: A

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Anonymous (e001)
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A
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Answer: B

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Anonymous (7a51)
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A
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Answer: A
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Anonymous (ea5b)
A
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A
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Answer: C

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Anonymous (7fcf)
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Answer: A

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Anonymous (84e2)
A
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Answer: C

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Anonymous (ba84)
A
1 Vote
Which of the following is the greatest?
[imath]\text{(A) } \frac{3}{7} \quad \text{(B) } \frac{5}{6} \quad \text{(C) } \frac{7}{10} \quad \text{(D) } \frac{4}{5}[/imath]

Answer: B

We basically do long division of top divided by bottom.

[imath]A : \frac{3}{7} = 3 \div 7 \approx 0.428[/imath]
[imath]B : \frac{5}{6}...[/imath]
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0 Votes
A
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Answer: A

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Anonymous (cfa5)
A
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If [imath]x = 3[/imath], what is [imath]x \cdot x(x)[/imath]?
[imath]\text{(A) } 27 \quad \text{(B) } 18 \quad \text{(C) } 9 \quad \text{(D) } 6[/imath]

Answer: A

We are given:
[imath]x = 3[/imath]

and we need to find:
[imath]x \cdot x(x)[/imath]


Step 1: Simplify the expression
We are multiplying [imath]x[/imath] by [imath]x(x)[/imath]...
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Solve [imath]4![/imath]
[imath]\text{(A) } 16 \quad \text{(B) } 24 \quad \text{(C) } 12 \quad \text{(D) } 8[/imath]
Answer: B

Step 1: Recall that [imath]4![/imath] means:
[imath]4! = 4 \times 3 \times 2 \times 1[/imath]


Step 2: Multiply:
[imath]4 \times 3 = 12[/imath]
[imath]12 \times 2 = 24[/imath]
[imath]24 \times 1 = 24[/imath]


✅...
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Answer: A

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Anonymous (edf1)
A
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Answer: C

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Anonymous (0182)
A
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A
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Answer: B

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Anonymous (10d8)
A
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Expand: [imath](x + 3)(x + 7)[/imath]

[imath]\text{(A) } x^2 + 10x + 21 \quad \\ \text{(B) } x^2 + 9x + 20 \quad \\ \text{(C) } x^2 + 7x + 21 \quad \\ \text{(D) } x^2 + 10x + 20[/imath]

Answer: A


Step 1: Expand using FOIL:
[imath](x + 3)(x + 7) = \underbrace{x \cdot x}_{\text{First}} + \underbrace{x \cdot...[/imath]
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Answer: A

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Anonymous (ae42)
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Answer: A

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Anonymous (b96c)
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Answer: A
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Anonymous (f7e6)
A
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